What is the domain of f(x)=sqrt((3-2x)) ?

The domain of f(x)=sqrt((3-2x)) is x<= 3/2

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domain of f(x)=sqrt((3-2x))

domain

f (x) = (3 - 2 x)

x \leq \frac{3}{2}

Interval Notation

(- \infty, \frac{3}{2}]

Solution steps

Find non-negative values for radicals:

x \leq \frac{3}{2}

The function domain

x \leq \frac{3}{2}

f (x) = x^{2} + 2

f (x) = x^{3} - 6 x^{2} - 15 x + 4

y = 2 - x

\frac{x - 3}{( x + 4 ) ^{2}}

f (x) = x e^{2 x}

What is the domain of f(x)=sqrt((3-2x)) ?
The domain of f(x)=sqrt((3-2x)) is x<= 3/2