What is the inverse of f(x)=2(x-2)^2+1 ?

The inverse of f(x)=2(x-2)^2+1 is sqrt((x-1)/2)+2,-sqrt((x-1)/2)+2

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inverse of f(x)=2(x-2)^2+1

inverse

f (x) = 2 (x - 2)^{2} + 1

\frac{x - 1}{2} + 2, - \frac{x - 1}{2} + 2

Solution steps

y = 2 (x - 2)^{2} + 1

Replace

x

with

y

x = 2 (y - 2)^{2} + 1

Solve for

y, x = 2 (y - 2)^{2} + 1

\frac{x - 1}{2} + 2, - \frac{x - 1}{2} + 2

ln (6 - 2 X)

f (x) = (\frac{3}{4})^{2 x}

f (x) = \frac{x ^{5}}{32}

y = \frac{1}{2} x + 7

x^{\frac{3}{2}}

What is the inverse of f(x)=2(x-2)^2+1 ?
The inverse of f(x)=2(x-2)^2+1 is sqrt((x-1)/2)+2,-sqrt((x-1)/2)+2