What is the inverse of f(x)=8x^2+10 ?

The inverse of f(x)=8x^2+10 is (sqrt(2)sqrt(x-10))/4 ,-(sqrt(2)sqrt(x-10))/4

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inverse of f(x)=8x^2+10

inverse

f (x) = 8 x^{2} + 10

\frac{2 x - 10}{4}, - \frac{2 x - 10}{4}

Solution steps

y = 8 x^{2} + 10

Replace

x

with

y

x = 8 y^{2} + 10

Solve for

y, x = 8 y^{2} + 10

\frac{2 x - 10}{4}, - \frac{2 x - 10}{4}

f (x) = 3 x^{- \frac{2}{5}}

f (x) = \frac{7}{2 x + 5}

\frac{2 - x}{3 + x}

\frac{2 x}{5 - x}

f (x) = 38 - 1.25 x

What is the inverse of f(x)=8x^2+10 ?
The inverse of f(x)=8x^2+10 is (sqrt(2)sqrt(x-10))/4 ,-(sqrt(2)sqrt(x-10))/4