What is the inverse of f(x)=9x^2+7x ?

The inverse of f(x)=9x^2+7x is (-7+sqrt(49+36x))/(18),(-7-sqrt(49+36x))/(18)

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inverse of f(x)=9x^2+7x

inverse

f (x) = 9 x^{2} + 7 x

\frac{- 7 + 49 + 36 x}{18}, \frac{- 7 - 49 + 36 x}{18}

Solution steps

y = 9 x^{2} + 7 x

Replace

x

with

y

x = 9 y^{2} + 7 y

Solve for

y, x = 9 y^{2} + 7 y

\frac{- 7 + 49 + 36 x}{18}, \frac{- 7 - 49 + 36 x}{18}

f (x) = - 13 x

f (x) = x + 19

f (x) = x^{2 + 5}

3 + 6 + 7 x

f (x) = \frac{( 2 x - 3 )}{4}

What is the inverse of f(x)=9x^2+7x ?
The inverse of f(x)=9x^2+7x is (-7+sqrt(49+36x))/(18),(-7-sqrt(49+36x))/(18)