What is the inverse of f(x)=-2x^2+7 ?

The inverse of f(x)=-2x^2+7 is sqrt(-(x-7)/2),-sqrt(-(x-7)/2)

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inverse of f(x)=-2x^2+7

inverse

f (x) = - 2 x^{2} + 7

- \frac{x - 7}{2}, - - \frac{x - 7}{2}

Solution steps

y = - 2 x^{2} + 7

Replace

x

with

y

x = - 2 y^{2} + 7

Solve for

y, x = - 2 y^{2} + 7

- \frac{x - 7}{2}, - - \frac{x - 7}{2}

f (x) = - 2 x^{2} + 3

y = \frac{3 x x}{8}

f (x) = lo g_{2} (2 x - 12)

f (x) = - 3 {-, 3 \leq x \leq 3}

f (x) = 2 - ln (1 + e^{2 x})

What is the inverse of f(x)=-2x^2+7 ?
The inverse of f(x)=-2x^2+7 is sqrt(-(x-7)/2),-sqrt(-(x-7)/2)