What is the inverse of \sqrt[5]{-x}+1 ?

The inverse of \sqrt[5]{-x}+1 is -x^5+5x^4-10x^3+10x^2-5x+1

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inverse of \sqrt[5]{-x}+1

inverse

- x^{5} + 5 x^{4} - 10 x^{3} + 10 x^{2} - 5 x + 1

Solution steps

Replace

x

with

y

Solve for

- x^{5} + 5 x^{4} - 10 x^{3} + 10 x^{2} - 5 x + 1

f (x) = \frac{9}{5 + x}

f (x) = 5 x - 2 + 2

f (x) = \frac{2 x - 8}{1 - 7 x} - 10

g (x) = \frac{x}{5} - 8

\frac{6 x}{5} + 3

What is the inverse of \sqrt[5]{-x}+1 ?
The inverse of \sqrt[5]{-x}+1 is -x^5+5x^4-10x^3+10x^2-5x+1