What is the inverse of x^4-8x^2+16 ?

The inverse of x^4-8x^2+16 is sqrt(4+\sqrt{x)},-sqrt(4+\sqrt{x)},sqrt(4-\sqrt{x)},-sqrt(4-\sqrt{x)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of x^4-8x^2+16

inverse

x^{4} - 8 x^{2} + 16

4 + x, - 4 + x, 4 - x, - 4 - x

Solution steps

y = x^{4} - 8 x^{2} + 16

Replace

x

with

y

x = y^{4} - 8 y^{2} + 16

Solve for

y, x = y^{4} - 8 y^{2} + 16

4 + x, - 4 + x, 4 - x, - 4 - x

f (x) = 5 - x + 8

\frac{3}{x + 3}

(9 x - 2) x 3

\frac{d}{d} x^{3} - 3

f (x) = 3 e^{x} + 2

What is the inverse of x^4-8x^2+16 ?
The inverse of x^4-8x^2+16 is sqrt(4+\sqrt{x)},-sqrt(4+\sqrt{x)},sqrt(4-\sqrt{x)},-sqrt(4-\sqrt{x)}