What is the inverse of (6x)/(sqrt(x^2-1)) ?

The inverse of (6x)/(sqrt(x^2-1)) is (xsqrt(x^2-36))/(x^2-36),-(xsqrt(x^2-36))/(x^2-36)

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inverse of (6x)/(sqrt(x^2-1))

inverse

\frac{6 x}{x ^{2} - 1}

\frac{x x ^{2} - 36}{x ^{2} - 36}, - \frac{x x ^{2} - 36}{x ^{2} - 36}

Solution steps

y = \frac{6 x}{x ^{2} - 1}

Replace

x

with

y

x = \frac{6 y}{y ^{2} - 1}

Solve for

y, x = \frac{6 y}{y ^{2} - 1}

\frac{x x ^{2} - 36}{x ^{2} - 36}, - \frac{x x ^{2} - 36}{x ^{2} - 36}

\frac{2}{x + 2}

csch (x)

f (x) = (x - 4) + 6

f (x) = (\frac{8 ^{x}}{5})^{7}

f (x) = \frac{1}{2} - 2

What is the inverse of (6x)/(sqrt(x^2-1)) ?
The inverse of (6x)/(sqrt(x^2-1)) is (xsqrt(x^2-36))/(x^2-36),-(xsqrt(x^2-36))/(x^2-36)