What is the inverse of y=cos^2(x) ?

The inverse of y=cos^2(x) is arccos(sqrt(x)),arccos(-sqrt(x))

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inverse of y=cos^2(x)

inverse

y = cos^{2} (x)

arccos (x), arccos (- x)

Solution steps

Solve for

cos (x), y = cos^{2} (x)

cos (x) = y, cos (x) = - y

cos (a) = b \Rightarrow a = arccos (b)

arccos (y), arccos (- y)

Substitute

y = x

arccos (x), arccos (- x)

y = - csc (\frac{8}{9}) x

f (x) = - \frac{1}{5} x - 3

f (x) = 30.5 - 2.5 x

f (x) = 2 x^{5} - 3

\frac{2 x + 1}{x}

What is the inverse of y=cos^2(x) ?
The inverse of y=cos^2(x) is arccos(sqrt(x)),arccos(-sqrt(x))