What is the inverse of f(x)=(0.2)^{-x}+1 ?

The inverse of f(x)=(0.2)^{-x}+1 is -(ln(x-1))/(ln(0.2))

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inverse of f(x)=(0.2)^{-x}+1

inverse

f (x) = (0.2)^{- x} + 1

- \frac{ln ( x - 1 )}{ln ( 0.2 )}

Solution steps

y = 0. 2^{- x} + 1

Replace

x

with

y

x = 0. 2^{- y} + 1

Solve for

y, x = 0. 2^{- y} + 1

- \frac{ln ( x - 1 )}{ln ( 0.2 )}

\frac{x + 1}{2 x}

7 x + 12

\frac{( 5 x - 3 )}{4 x + 5}

f (x) = 1 - 2 x - 1

What is the inverse of f(x)=(0.2)^{-x}+1 ?
The inverse of f(x)=(0.2)^{-x}+1 is -(ln(x-1))/(ln(0.2))