What is the inverse of f(t)=30-30e^{-ln(10)t} ?

The inverse of f(t)=30-30e^{-ln(10)t} is -(ln(-\frac{t-30)/(30))}{ln(10)}

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inverse of f(t)=30-30e^{-ln(10)t}

inverse

f (t) = 30 - 30 e^{- l n (10) t}

- \frac{ln ( - \frac{t - 30}{30} )}{ln ( 10 )}

Solution steps

y = 30 - 30 e^{- l n (10) t}

Replace

t

with

y

t = 30 - 30 e^{- l n (10) y}

Solve for

y, t = 30 - 30 e^{- l n (10) y}

- \frac{ln ( - \frac{t - 30}{30} )}{ln ( 10 )}

y = - x^{2} + 1

1 + x + 6

f (x) = 4 x + 17

f (x) = \frac{( x - 10 ) ^{7}}{7}

sin (- \frac{2}{2})

What is the inverse of f(t)=30-30e^{-ln(10)t} ?
The inverse of f(t)=30-30e^{-ln(10)t} is -(ln(-\frac{t-30)/(30))}{ln(10)}