What is the inverse of f(x)=sqrt(x^2-3) ?

The inverse of f(x)=sqrt(x^2-3) is sqrt(x^2+3),-sqrt(x^2+3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=sqrt(x^2-3)

inverse

f (x) = x^{2} - 3

x^{2} + 3, - x^{2} + 3

Solution steps

y = x^{2} - 3

Replace

x

with

y

x = y^{2} - 3

Solve for

y, x = y^{2} - 3

x^{2} + 3, - x^{2} + 3

f (x) = - 3 x^{2} - 2

f (x) = 10.4 - 4 t

47 x - 55

+ x^{2} + 6

f (x) = (4 x)^{- \frac{5}{4}}

What is the inverse of f(x)=sqrt(x^2-3) ?
The inverse of f(x)=sqrt(x^2-3) is sqrt(x^2+3),-sqrt(x^2+3)