What is the inverse of g(x)=3x^2-4 ?

The inverse of g(x)=3x^2-4 is sqrt((x+4)/3),-sqrt((x+4)/3)

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inverse of g(x)=3x^2-4

inverse

g (x) = 3 x^{2} - 4

\frac{x + 4}{3}, - \frac{x + 4}{3}

Solution steps

y = 3 x^{2} - 4

Replace

x

with

y

x = 3 y^{2} - 4

Solve for

y, x = 3 y^{2} - 4

\frac{x + 4}{3}, - \frac{x + 4}{3}

4 x + 16

f (x) = - 9 x - 6

f (x) = - \frac{1}{2} x + 6

f (x) = 2 x - 14

f (x) = 2 x - 26

What is the inverse of g(x)=3x^2-4 ?
The inverse of g(x)=3x^2-4 is sqrt((x+4)/3),-sqrt((x+4)/3)