What is the inverse of f(x)=2sqrt(1/3 x)+1 ?

The inverse of f(x)=2sqrt(1/3 x)+1 is (3x^2+3)/4-(3x)/2

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inverse of f(x)=2sqrt(1/3 x)+1

inverse

f (x) = 2 \frac{1}{3} x + 1

\frac{3 x ^{2} + 3}{4} - \frac{3 x}{2}

Solution steps

y = 2 \frac{1}{3} x + 1

Replace

x

with

y

x = 2 \frac{1}{3} y + 1

Solve for

y, x = 2 \frac{1}{3} y + 1

\frac{3 x ^{2} + 3}{4} - \frac{3 x}{2}

ln (2 x - 3)

f (x) = 3 - e^{- 2 x}

f (x) = \frac{7 x}{5 x - 2}

f (x) = \frac{4}{x} - 3

f (x) = \frac{2 x - 5}{6}

What is the inverse of f(x)=2sqrt(1/3 x)+1 ?
The inverse of f(x)=2sqrt(1/3 x)+1 is (3x^2+3)/4-(3x)/2