What is the inverse of y=4x^2+4x+1 ?

The inverse of y=4x^2+4x+1 is (-1+sqrt(x))/2 ,-(sqrt(x)+1)/2

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inverse of y=4x^2+4x+1

inverse

y = 4 x^{2} + 4 x + 1

\frac{- 1 + x}{2}, - \frac{x + 1}{2}

Solution steps

y = 4 x^{2} + 4 x + 1

Replace

x

with

y

x = 4 y^{2} + 4 y + 1

Solve for

y, x = 4 y^{2} + 4 y + 1

\frac{- 1 + x}{2}, - \frac{x + 1}{2}

3 e^{3 x}

f (x) = 6 x - 30

lo g_{\frac{1}{4}} (x^{5})

f (x) = \frac{5}{x} + 2

f (x) = \frac{- 2 ( x - 4 ) + 15}{x - 4}

What is the inverse of y=4x^2+4x+1 ?
The inverse of y=4x^2+4x+1 is (-1+sqrt(x))/2 ,-(sqrt(x)+1)/2