What is the inverse of f(x)=100(1-t/(50))^2 ?

The inverse of f(x)=100(1-t/(50))^2 is -5sqrt(t)+50,5sqrt(t)+50

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inverse of f(x)=100(1-t/(50))^2

inverse

f (x) = 100 (1 - \frac{t}{50})^{2}

- 5 t + 50, 5 t + 50

Solution steps

x = 100 (1 - \frac{t}{50})^{2}

Replace

t

with

x

t = 100 (1 - \frac{x}{50})^{2}

Solve for

x, t = 100 (1 - \frac{x}{50})^{2}

- 5 t + 50, 5 t + 50

f (x) = \frac{9 x + 3}{2}

f (x) = \frac{7 x}{x + 5}

f (x) = 4 + 6 + 11 x

f (x) = 2 - lo g_{9} (x)

f (x) = \frac{1}{( 1 + x ) ^{2}}

What is the inverse of f(x)=100(1-t/(50))^2 ?
The inverse of f(x)=100(1-t/(50))^2 is -5sqrt(t)+50,5sqrt(t)+50