What is the inverse of f(x)=log_{2}(3x+4)-5 ?

The inverse of f(x)=log_{2}(3x+4)-5 is (2^{x+5}-4)/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=log_{2}(3x+4)-5

inverse

f (x) = lo g_{2} (3 x + 4) - 5

\frac{2 ^{x + 5} - 4}{3}

Solution steps

y = lo g_{2} (3 x + 4) - 5

Replace

x

with

y

x = lo g_{2} (3 y + 4) - 5

Solve for

y, x = lo g_{2} (3 y + 4) - 5

\frac{2 ^{x + 5} - 4}{3}

f (x) = \frac{4 - x}{x}

f (x) = 7 x^{2} - 2

f (x) = \frac{5}{9} (x - 32) + 273.15

f (x) = \frac{( 2 x + 5 )}{( x + 7 )}

y = 2^{c o s (x)}

What is the inverse of f(x)=log_{2}(3x+4)-5 ?
The inverse of f(x)=log_{2}(3x+4)-5 is (2^{x+5}-4)/3