What is the inverse of f(x)=((x+3))/((x-3)) ?

The inverse of f(x)=((x+3))/((x-3)) is (3+3x)/(x-1)

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inverse of f(x)=((x+3))/((x-3))

inverse

f (x) = \frac{( x + 3 )}{( x - 3 )}

\frac{3 + 3 x}{x - 1}

Solution steps

y = \frac{x + 3}{x - 3}

Replace

x

with

y

x = \frac{y + 3}{y - 3}

Solve for

y, x = \frac{y + 3}{y - 3}

\frac{3 + 3 x}{x - 1}

f (x) = 4 x + 4

y = \frac{1}{3} \cdot e^{2 x}

1 - 2 x

f (x) = - 4 x^{3} - 4

f (x) = \frac{8 - 7 x}{6}

What is the inverse of f(x)=((x+3))/((x-3)) ?
The inverse of f(x)=((x+3))/((x-3)) is (3+3x)/(x-1)