What is the inverse of f(x)=(3^x)/(3^x+1) ?

The inverse of f(x)=(3^x)/(3^x+1) is (ln(-x/(x-1)))/(ln(3))

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inverse of f(x)=(3^x)/(3^x+1)

inverse

f (x) = \frac{3 ^{x}}{3 ^{x} + 1}

\frac{ln ( - \frac{x}{x - 1} )}{ln ( 3 )}

Solution steps

y = \frac{3 ^{x}}{3 ^{x} + 1}

Replace

x

with

y

x = \frac{3 ^{y}}{3 ^{y} + 1}

Solve for

y, x = \frac{3 ^{y}}{3 ^{y} + 1}

\frac{ln ( - \frac{x}{x - 1} )}{ln ( 3 )}

f (x) = arccos (- 1)

f (x) = \frac{7}{x ^{2}}

lo g_{2} (x - 5) - 8

y = \frac{1 + 3 x}{5 - 2 x}

y = \frac{2}{3} x + 1

What is the inverse of f(x)=(3^x)/(3^x+1) ?
The inverse of f(x)=(3^x)/(3^x+1) is (ln(-x/(x-1)))/(ln(3))