What is the inverse of y=(x^2)/2-2x+1 ?

The inverse of y=(x^2)/2-2x+1 is (4+sqrt(8x+8))/2 ,(4-sqrt(8x+8))/2

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inverse of y=(x^2)/2-2x+1

inverse

y = \frac{x ^{2}}{2} - 2 x + 1

\frac{4 + 8 x + 8}{2}, \frac{4 - 8 x + 8}{2}

Solution steps

y = \frac{x ^{2}}{2} - 2 x + 1

Replace

x

with

y

x = \frac{y ^{2}}{2} - 2 y + 1

Solve for

y, x = \frac{y ^{2}}{2} - 2 y + 1

\frac{4 + 8 x + 8}{2}, \frac{4 - 8 x + 8}{2}

f (x) = \frac{2 x}{3 x - 4}

f (x) = 5 + 3 x

f (x) = 1 - \frac{1}{4} x

f (x) = 2 - 3 x

f (x) = \frac{4}{1 + ln ( 1 + e ^{x} )}

What is the inverse of y=(x^2)/2-2x+1 ?
The inverse of y=(x^2)/2-2x+1 is (4+sqrt(8x+8))/2 ,(4-sqrt(8x+8))/2