What is the inverse of f(x)=-4-(sqrt(16-(x-3)^2))/2 ?

The inverse of f(x)=-4-(sqrt(16-(x-3)^2))/2 is 3-2sqrt(-x^2-8x-12),2sqrt(-x^2-8x-12)+3

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inverse of f(x)=-4-(sqrt(16-(x-3)^2))/2

inverse

f (x) = - 4 - \frac{16 - ( x - 3 ) ^{2}}{2}

3 - 2 - x^{2} - 8 x - 12, 2 - x^{2} - 8 x - 12 + 3

Solution steps

y = - 4 - \frac{16 - ( x - 3 ) ^{2}}{2}

Replace

x

with

y

x = - 4 - \frac{16 - ( y - 3 ) ^{2}}{2}

Solve for

y, x = - 4 - \frac{16 - ( y - 3 ) ^{2}}{2}

3 - 2 - x^{2} - 8 x - 12, 2 - x^{2} - 8 x - 12 + 3

y = 1 + 6 + 8 x

\frac{- 16 a + 5}{3}

\frac{10 - 3 x}{1 + 2 x}

f (x) = \frac{x ^{\frac{1}{7}} + 9}{4} - 8

f (x) = 10 x - 10

What is the inverse of f(x)=-4-(sqrt(16-(x-3)^2))/2 ?
The inverse of f(x)=-4-(sqrt(16-(x-3)^2))/2 is 3-2sqrt(-x^2-8x-12),2sqrt(-x^2-8x-12)+3