What is the inverse of f(x)=4x^2+12x+8 ?

The inverse of f(x)=4x^2+12x+8 is (-3+sqrt(x+1))/2 ,-(sqrt(x+1)+3)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=4x^2+12x+8

inverse

f (x) = 4 x^{2} + 12 x + 8

\frac{- 3 + x + 1}{2}, - \frac{x + 1 + 3}{2}

Solution steps

y = 4 x^{2} + 12 x + 8

Replace

x

with

y

x = 4 y^{2} + 12 y + 8

Solve for

y, x = 4 y^{2} + 12 y + 8

\frac{- 3 + x + 1}{2}, - \frac{x + 1 + 3}{2}

4 x - 5

f (x) = - 6 x^{2} - 3

f (x) = x - 7 + 3

y = ln (x - 2)

f (x) = 6 - 7 x^{3}

What is the inverse of f(x)=4x^2+12x+8 ?
The inverse of f(x)=4x^2+12x+8 is (-3+sqrt(x+1))/2 ,-(sqrt(x+1)+3)/2