What is the inverse of g(a)=a^2+8a-7 ?

The inverse of g(a)=a^2+8a-7 is -4+sqrt(a+23),-sqrt(a+23)-4

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inverse of g(a)=a^2+8a-7

inverse

g (a) = a^{2} + 8 a - 7

- 4 + a + 23, - a + 23 - 4

Solution steps

y = a^{2} + 8 a - 7

Replace

a

with

y

a = y^{2} + 8 y - 7

Solve for

y, a = y^{2} + 8 y - 7

- 4 + a + 23, - a + 23 - 4

3^{9^{x}}

g (x) = x^{2} + 3

lo g_{5} (2 x)

6 x - 12

What is the inverse of g(a)=a^2+8a-7 ?
The inverse of g(a)=a^2+8a-7 is -4+sqrt(a+23),-sqrt(a+23)-4