What is the inverse of f(x)=(19)/(x^2) ?

The inverse of f(x)=(19)/(x^2) is sqrt((19)/x),-sqrt((19)/x)

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inverse of f(x)=(19)/(x^2)

inverse

f (x) = \frac{19}{x ^{2}}

\frac{19}{x}, - \frac{19}{x}

Solution steps

y = \frac{19}{x ^{2}}

Replace

x

with

y

x = \frac{19}{y ^{2}}

Solve for

y, x = \frac{19}{y ^{2}}

\frac{19}{x}, - \frac{19}{x}

y = x - 3

f (x) = 4 (2.3)^{x}

x^{2} + 4 x + 1

f (x) = \frac{1}{x ^{2}}, x > 0

What is the inverse of f(x)=(19)/(x^2) ?
The inverse of f(x)=(19)/(x^2) is sqrt((19)/x),-sqrt((19)/x)