What is the domain of 1/(\sqrt[4]{x^2-5x)} ?

The domain of 1/(\sqrt[4]{x^2-5x)} is x 5

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domain of 1/(\sqrt[4]{x^2-5x)}

domain

x < 0 or x > 5

Interval Notation

(- \infty, 0) \cup (5, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 0 or x \geq 5

Find undefined (singularity) points:

x = 5, x = 0

Combine real regions and undefined points for final function domain

x < 0 or x > 5

f (x) = 48 x - 4 x^{2}

f (x) = sin (\frac{1}{2}) (x + π) + 4

f (x) = 2 (3)^{x + 4} - 8

- 2 cos (5 x)

(2, 0), (0, - 2)

What is the domain of 1/(\sqrt[4]{x^2-5x)} ?
The domain of 1/(\sqrt[4]{x^2-5x)} is x<0\lor x>5