What is the inverse of f(x)=4x^2+5 ?

The inverse of f(x)=4x^2+5 is (sqrt(x-5))/2 ,-(sqrt(x-5))/2

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inverse of f(x)=4x^2+5

inverse

f (x) = 4 x^{2} + 5

\frac{x - 5}{2}, - \frac{x - 5}{2}

Solution steps

y = 4 x^{2} + 5

Replace

x

with

y

x = 4 y^{2} + 5

Solve for

y, x = 4 y^{2} + 5

\frac{x - 5}{2}, - \frac{x - 5}{2}

\frac{x - 2}{2 x + 3}

\frac{1}{e ^{x}}

f (x) = - 3 + \frac{7}{5} x

ln (x + 3) - 4

f (x) = 7 x^{2} - 11

What is the inverse of f(x)=4x^2+5 ?
The inverse of f(x)=4x^2+5 is (sqrt(x-5))/2 ,-(sqrt(x-5))/2