What is the inverse of f(x)=(x^{1/3}+10)/3 ?

The inverse of f(x)=(x^{1/3}+10)/3 is 27x^3-270x^2+900x-1000

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inverse of f(x)=(x^{1/3}+10)/3

inverse

f (x) = \frac{x ^{\frac{1}{3}} + 10}{3}

27 x^{3} - 270 x^{2} + 900 x - 1000

Solution steps

y = \frac{x ^{\frac{1}{3}} + 10}{3}

Replace

x

with

y

x = \frac{y ^{\frac{1}{3}} + 10}{3}

Solve for

y, x = \frac{y ^{\frac{1}{3}} + 10}{3}

27 x^{3} - 270 x^{2} + 900 x - 1000

f (x) = lo g_{6} (x - 3)

f (x) = ln (5 - 4 x)

y - 1

y = x^{2} + 6

What is the inverse of f(x)=(x^{1/3}+10)/3 ?
The inverse of f(x)=(x^{1/3}+10)/3 is 27x^3-270x^2+900x-1000