What is the inverse of f(x)=(sqrt(x+2))/(x+1) ?

The inverse of f(x)=(sqrt(x+2))/(x+1) is (-2x^2+1+sqrt(4x^2+1))/(2x^2),(-2x^2+1-sqrt(4x^2+1))/(2x^2)

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inverse of f(x)=(sqrt(x+2))/(x+1)

inverse

f (x) = \frac{x + 2}{x + 1}

\frac{- 2 x ^{2} + 1 + 4 x ^{2} + 1}{2 x ^{2}}, \frac{- 2 x ^{2} + 1 - 4 x ^{2} + 1}{2 x ^{2}}

Solution steps

y = \frac{x + 2}{x + 1}

Replace

x

with

y

x = \frac{y + 2}{y + 1}

Solve for

y, x = \frac{y + 2}{y + 1}

\frac{- 2 x ^{2} + 1 + 4 x ^{2} + 1}{2 x ^{2}}, \frac{- 2 x ^{2} + 1 - 4 x ^{2} + 1}{2 x ^{2}}

ln (2 + e^{x - 3})

3 - x + 2

2 x^{2} - x

f (x) = \frac{( 2 x + 5 )}{3}

f (x) = lo g_{13} (x)

What is the inverse of f(x)=(sqrt(x+2))/(x+1) ?
The inverse of f(x)=(sqrt(x+2))/(x+1) is (-2x^2+1+sqrt(4x^2+1))/(2x^2),(-2x^2+1-sqrt(4x^2+1))/(2x^2)