What is the inverse of ((x-6)(x+6))/(x^2-9) ?

The inverse of ((x-6)(x+6))/(x^2-9) is (sqrt(-(x-1)(-9x+36)))/(x-1),-(sqrt(-(x-1)(-9x+36)))/(x-1)

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inverse of ((x-6)(x+6))/(x^2-9)

inverse

\frac{( x - 6 ) ( x + 6 )}{x ^{2} - 9}

\frac{- ( x - 1 ) ( - 9 x + 36 )}{x - 1}, - \frac{- ( x - 1 ) ( - 9 x + 36 )}{x - 1}

Solution steps

y = \frac{( x - 6 ) ( x + 6 )}{x ^{2} - 9}

Replace

x

with

y

x = \frac{( y - 6 ) ( y + 6 )}{y ^{2} - 9}

Solve for

y, x = \frac{( y - 6 ) ( y + 6 )}{y ^{2} - 9}

\frac{- ( x - 1 ) ( - 9 x + 36 )}{x - 1}, - \frac{- ( x - 1 ) ( - 9 x + 36 )}{x - 1}

f (x) = arccsc (2)

f (x) = - 3 x + \frac{6}{7}

g (x) = (x - 9)^{2}, x \geq 9

f (x) = - 1 0^{(x + 2)} - 3

e^{x - 3}

What is the inverse of ((x-6)(x+6))/(x^2-9) ?
The inverse of ((x-6)(x+6))/(x^2-9) is (sqrt(-(x-1)(-9x+36)))/(x-1),-(sqrt(-(x-1)(-9x+36)))/(x-1)