What is the inverse of f(x)=300(1+(0.05)/(12))^{12x} ?

The inverse of f(x)=300(1+(0.05)/(12))^{12x} is (ln(x/(300)))/(12ln(\frac{12.05){12})}

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inverse of f(x)=300(1+(0.05)/(12))^{12x}

inverse

f (x) = 300 (1 + \frac{0.05}{12})^{12 x}

\frac{ln ( \frac{x}{300} )}{12 ln ( \frac{12.05}{12} )}

Solution steps

y = 300 (1 + \frac{0.05}{12})^{12 x}

Replace

x

with

y

x = 300 (1 + \frac{0.05}{12})^{12 y}

Solve for

y, x = 300 (1 + \frac{0.05}{12})^{12 y}

\frac{ln ( \frac{x}{300} )}{12 ln ( \frac{12.05}{12} )}

f (x) = 3 + \frac{1}{x - 1}

f (x) = 6^{x} + 5

y = - x^{2} + 10

g (x) = 3 x + 4

What is the inverse of f(x)=300(1+(0.05)/(12))^{12x} ?
The inverse of f(x)=300(1+(0.05)/(12))^{12x} is (ln(x/(300)))/(12ln(\frac{12.05){12})}