What is the inverse of (4x)^{-2/5} ?

The inverse of (4x)^{-2/5} is 1/(4x^{5/2)},-1/(4x^{5/2)}

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inverse of (4x)^{-2/5}

inverse

(4 x)^{- \frac{2}{5}}

\frac{1}{4 x ^{\frac{5}{2}}}, - \frac{1}{4 x ^{\frac{5}{2}}}

Solution steps

y = (4 x)^{- \frac{2}{5}}

Replace

x

with

y

x = (4 y)^{- \frac{2}{5}}

Solve for

y, x = (4 y)^{- \frac{2}{5}}

\frac{1}{4 x ^{\frac{5}{2}}}, - \frac{1}{4 x ^{\frac{5}{2}}}

3 x^{2} - 5

3 x^{2} - 7

0. 4^{x}

f (x) = 2 x - 1

f (x) = \frac{1}{x + 3} + 1

What is the inverse of (4x)^{-2/5} ?
The inverse of (4x)^{-2/5} is 1/(4x^{5/2)},-1/(4x^{5/2)}