What is the inverse of f(x)=x^2-10,x>= 0 ?

The inverse of f(x)=x^2-10,x>= 0 is sqrt(x+10),-sqrt(x+10)

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inverse of f(x)=x^2-10,x>= 0

inverse

f (x) = x^{2} - 10, x \geq 0

x + 10, - x + 10

Solution steps

y = x^{2} - 10

Replace

x

with

y

x = y^{2} - 10

Solve for

y, x = y^{2} - 10

x + 10, - x + 10

- 2 + lo g_{5} (x - 4)

f (x) = \frac{5 x - 2}{3 x}

f (x) = \frac{3 x + 10}{x + 3}

f (x) = 3 - e^{x}

f (x) = e^{x + 1}

What is the inverse of f(x)=x^2-10,x>= 0 ?
The inverse of f(x)=x^2-10,x>= 0 is sqrt(x+10),-sqrt(x+10)