What is the inverse of f(x)=-8x^2+11 ?

The inverse of f(x)=-8x^2+11 is sqrt(-(x-11)/8),-sqrt(-(x-11)/8)

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inverse of f(x)=-8x^2+11

inverse

f (x) = - 8 x^{2} + 11

- \frac{x - 11}{8}, - - \frac{x - 11}{8}

Solution steps

y = - 8 x^{2} + 11

Replace

x

with

y

x = - 8 y^{2} + 11

Solve for

y, x = - 8 y^{2} + 11

- \frac{x - 11}{8}, - - \frac{x - 11}{8}

f (x) = (x + 2)^{5} - 3

f (x) = (x + 2)^{5} + 1

f (x) = - 4 + ln (x)

f (x) = \frac{1}{π} arctan (x) + \frac{1}{2}

What is the inverse of f(x)=-8x^2+11 ?
The inverse of f(x)=-8x^2+11 is sqrt(-(x-11)/8),-sqrt(-(x-11)/8)