What is the inverse of f(x)=8^{x+1}-3 ?

The inverse of f(x)=8^{x+1}-3 is (ln(x+3))/(3ln(2))-1

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inverse of f(x)=8^{x+1}-3

inverse

f (x) = 8^{x + 1} - 3

\frac{ln ( x + 3 )}{3 ln ( 2 )} - 1

Solution steps

y = 8^{x + 1} - 3

Replace

x

with

y

x = 8^{y + 1} - 3

Solve for

y, x = 8^{y + 1} - 3

\frac{ln ( x + 3 )}{3 ln ( 2 )} - 1

x^{2} - 2 x - 1

f (x) = \frac{x ^{2} - 4}{x + 3}

f (x) = - 11 - x

\frac{2}{x - 1}

f (x) = (\frac{( x - 1 )}{x - 2})

What is the inverse of f(x)=8^{x+1}-3 ?
The inverse of f(x)=8^{x+1}-3 is (ln(x+3))/(3ln(2))-1