What is the inverse of f(x)=(x-0.2)/(x+0.5) ?

The inverse of f(x)=(x-0.2)/(x+0.5) is (-0.2-0.5x)/(x-1)

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inverse of f(x)=(x-0.2)/(x+0.5)

inverse

f (x) = \frac{x - 0.2}{x + 0.5}

\frac{- 0.2 - 0.5 x}{x - 1}

Solution steps

y = \frac{x - 0.2}{x + 0.5}

Replace

x

with

y

x = \frac{y - 0.2}{y + 0.5}

Solve for

y, x = \frac{y - 0.2}{y + 0.5}

\frac{- 0.2 - 0.5 x}{x - 1}

\frac{3}{x ^{2} - 1}

f (x) = \frac{4 n + 16}{3}

f (x) = - \frac{3}{x + 1}

- 1 - x

f (x) = - (x - 2)^{3}

What is the inverse of f(x)=(x-0.2)/(x+0.5) ?
The inverse of f(x)=(x-0.2)/(x+0.5) is (-0.2-0.5x)/(x-1)