What is the inverse of f(x)=sqrt(2x^2-7) ?

The inverse of f(x)=sqrt(2x^2-7) is sqrt((x^2+7)/2),-sqrt((x^2+7)/2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=sqrt(2x^2-7)

inverse

f (x) = 2 x^{2} - 7

\frac{x ^{2} + 7}{2}, - \frac{x ^{2} + 7}{2}

Solution steps

y = 2 x^{2} - 7

Replace

x

with

y

x = 2 y^{2} - 7

Solve for

y, x = 2 y^{2} - 7

\frac{x ^{2} + 7}{2}, - \frac{x ^{2} + 7}{2}

\frac{1}{2 - x}

sin (\frac{x}{2})

f (x) = 15 x + 12

f (x) = \frac{7}{x - 2}

f (x) = x \cdot 2

What is the inverse of f(x)=sqrt(2x^2-7) ?
The inverse of f(x)=sqrt(2x^2-7) is sqrt((x^2+7)/2),-sqrt((x^2+7)/2)