What is the inverse of f(x)=4sqrt(3-x)-7 ?

The inverse of f(x)=4sqrt(3-x)-7 is -(x^2+14x+1)/(16)

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inverse of f(x)=4sqrt(3-x)-7

inverse

f (x) = 4 3 - x - 7

- \frac{x ^{2} + 14 x + 1}{16}

Solution steps

y = 4 3 - x - 7

Replace

x

with

y

x = 4 3 - y - 7

Solve for

y, x = 4 3 - y - 7

- \frac{x ^{2} + 14 x + 1}{16}

f (x) = - x^{3} + 8

y = e^{- x^{2}}

f (x) = \frac{( 2 x - 6 )}{4}

f (x) = (x - 10)^{3} + 27

2 x + x + 5

What is the inverse of f(x)=4sqrt(3-x)-7 ?
The inverse of f(x)=4sqrt(3-x)-7 is -(x^2+14x+1)/(16)