What is the inverse of f(x)=\sqrt[3]{7x}+4 ?

The inverse of f(x)=\sqrt[3]{7x}+4 is (x^3-12x^2+48x-64)/7

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inverse of f(x)=\sqrt[3]{7x}+4

inverse

\frac{x ^{3} - 12 x ^{2} + 48 x - 64}{7}

Solution steps

Replace

x

with

y

Solve for

\frac{x ^{3} - 12 x ^{2} + 48 x - 64}{7}

f (x) = 7.5 x

f (x) = - 2 \frac{1}{5} x + 1 + 3

\frac{2}{x ^{3}}

\frac{1}{t}

sin (3 X)

What is the inverse of f(x)=\sqrt[3]{7x}+4 ?
The inverse of f(x)=\sqrt[3]{7x}+4 is (x^3-12x^2+48x-64)/7