What is the inverse of f(x)=((2x+1))/((3x-4)) ?

The inverse of f(x)=((2x+1))/((3x-4)) is (1+4x)/(3x-2)

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inverse of f(x)=((2x+1))/((3x-4))

inverse

f (x) = \frac{( 2 x + 1 )}{( 3 x - 4 )}

\frac{1 + 4 x}{3 x - 2}

Solution steps

y = \frac{2 x + 1}{3 x - 4}

Replace

x

with

y

x = \frac{2 y + 1}{3 y - 4}

Solve for

y, x = \frac{2 y + 1}{3 y - 4}

\frac{1 + 4 x}{3 x - 2}

\frac{2 x + 4}{x - 3}

f (x) = \frac{7 - x}{x}

+ \frac{6}{x + 1}

f (x) = 13.5 - 5 t

f (b) = (b + 6) (b - 2)

What is the inverse of f(x)=((2x+1))/((3x-4)) ?
The inverse of f(x)=((2x+1))/((3x-4)) is (1+4x)/(3x-2)