What is the inverse of (3x)/(x^2-16) ?

The inverse of (3x)/(x^2-16) is (3+sqrt(9+64x^2))/(2x),(3-sqrt(9+64x^2))/(2x)

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inverse of (3x)/(x^2-16)

inverse

\frac{3 x}{x ^{2} - 16}

\frac{3 + 9 + 64 x ^{2}}{2 x}, \frac{3 - 9 + 64 x ^{2}}{2 x}

Solution steps

y = \frac{3 x}{x ^{2} - 16}

Replace

x

with

y

x = \frac{3 y}{y ^{2} - 16}

Solve for

y, x = \frac{3 y}{y ^{2} - 16}

\frac{3 + 9 + 64 x ^{2}}{2 x}, \frac{3 - 9 + 64 x ^{2}}{2 x}

lo g_{3} (z)

f (x) = \frac{5 x - 3}{2 x - 5}

f (x) = \frac{5 x + 7}{x - 2}

f (x) = - 2 - \frac{1}{4} x

What is the inverse of (3x)/(x^2-16) ?
The inverse of (3x)/(x^2-16) is (3+sqrt(9+64x^2))/(2x),(3-sqrt(9+64x^2))/(2x)