What is the critical f(x)=(x-4)/(x^2+7) ?

The critical f(x)=(x-4)/(x^2+7) is x=4-sqrt(23),x=4+sqrt(23)

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critical f(x)=(x-4)/(x^2+7)

critical points

f (x) = \frac{x - 4}{x ^{2} + 7}

x = 4 - 23, x = 4 + 23

Solution steps

\frac{x - 4}{x ^{2} + 7}

Find where

f^{'} (x)

is equal to zero or undefined

x = 4 - 23, x = 4 + 23

Identify critical points not in

f (x)

domain

Domain of

\frac{x - 4}{x ^{2} + 7} : - \infty < x < \infty

All critical points are in domain

x = 4 - 23, x = 4 + 23

f (x) = \frac{3}{4} x + 5

f (x) = \frac{2 x ^{2} + 2 x}{x ^{2} - 4 x + 4}

x x - 4

x^{3}

y = \frac{4 x + 2}{3}

What is the critical f(x)=(x-4)/(x^2+7) ?
The critical f(x)=(x-4)/(x^2+7) is x=4-sqrt(23),x=4+sqrt(23)