What is the inverse of g(x)=-2x^2-3 ?

The inverse of g(x)=-2x^2-3 is sqrt(-(x+3)/2),-sqrt(-(x+3)/2)

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inverse of g(x)=-2x^2-3

inverse

g (x) = - 2 x^{2} - 3

- \frac{x + 3}{2}, - - \frac{x + 3}{2}

Solution steps

y = - 2 x^{2} - 3

Replace

x

with

y

x = - 2 y^{2} - 3

Solve for

y, x = - 2 y^{2} - 3

- \frac{x + 3}{2}, - - \frac{x + 3}{2}

g (x) = x - 1 - 2, x \geq 1

f (x) = 4 x^{2} - 2 + 2 x

1 + x^{2}

f (x) = \frac{2 x - 3}{3 x + 5}

V (t) = 32 - 20 e^{- 0.4 t}

What is the inverse of g(x)=-2x^2-3 ?
The inverse of g(x)=-2x^2-3 is sqrt(-(x+3)/2),-sqrt(-(x+3)/2)