What is the inverse of V(t)=32-20e^{-0.4t} ?

The inverse of V(t)=32-20e^{-0.4t} is -(ln(-\frac{t-32)/(20))}{0.4}

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inverse of V(t)=32-20e^{-0.4t}

inverse

V (t) = 32 - 20 e^{- 0.4 t}

- \frac{ln ( - \frac{t - 32}{20} )}{0.4}

Solution steps

y = 32 - 20 e^{- 0.4 t}

Replace

t

with

y

t = 32 - 20 e^{- 0.4 y}

Solve for

y, t = 32 - 20 e^{- 0.4 y}

- \frac{ln ( - \frac{t - 32}{20} )}{0.4}

f (x) = \frac{5}{x ^{2}}

f (x) = 4 x^{3} + 9

f (x) = 4 x - 5

g (x) = \frac{7 x + 11}{3}

f (x) = 2 x^{\frac{3}{5}}

What is the inverse of V(t)=32-20e^{-0.4t} ?
The inverse of V(t)=32-20e^{-0.4t} is -(ln(-\frac{t-32)/(20))}{0.4}