What is the inverse of f(x)=log_{2}(7x-10) ?

The inverse of f(x)=log_{2}(7x-10) is (2^x+10)/7

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inverse of f(x)=log_{2}(7x-10)

inverse

f (x) = lo g_{2} (7 x - 10)

\frac{2 ^{x} + 10}{7}

Solution steps

y = lo g_{2} (7 x - 10)

Replace

x

with

y

x = lo g_{2} (7 y - 10)

Solve for

y, x = lo g_{2} (7 y - 10)

\frac{2 ^{x} + 10}{7}

y = 41 - 1.25 h

2 x^{2} - 12 x + 5

x + 3 - 9

f (x) = lo g_{2} (a x - 4)

f (x) = \frac{1}{2} (x + 1)^{3}

What is the inverse of f(x)=log_{2}(7x-10) ?
The inverse of f(x)=log_{2}(7x-10) is (2^x+10)/7