What is the inverse of f(x)=ln(x^2+1) ?

The inverse of f(x)=ln(x^2+1) is sqrt(e^x-1),-sqrt(e^x-1)

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inverse of f(x)=ln(x^2+1)

inverse

f (x) = ln (x^{2} + 1)

e^{x} - 1, - e^{x} - 1

Solution steps

y = ln (x^{2} + 1)

Replace

x

with

y

x = ln (y^{2} + 1)

Solve for

y, x = ln (y^{2} + 1)

e^{x} - 1, - e^{x} - 1

g (x) = 49 x^{2}

f (x) = \frac{3 x - 2}{x + 4}

f (x) = - \frac{6}{x - 2}

f (x) = \frac{2}{x + 2} + 2

12 x^{7}

What is the inverse of f(x)=ln(x^2+1) ?
The inverse of f(x)=ln(x^2+1) is sqrt(e^x-1),-sqrt(e^x-1)