What is the inverse of f(x)=((x+2))/((ax-1)) ?

The inverse of f(x)=((x+2))/((ax-1)) is (2+x)/(ax-1)

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inverse of f(x)=((x+2))/((ax-1))

inverse

f (x) = \frac{( x + 2 )}{( a x - 1 )}

\frac{2 + x}{a x - 1}

Solution steps

y = \frac{x + 2}{a x - 1}

Replace

x

with

y

x = \frac{y + 2}{a y - 1}

Solve for

y, x = \frac{y + 2}{a y - 1}

\frac{2 + x}{a x - 1}

sin (\frac{π}{6})

y = 5 - 9 x

y = 7 x^{2} - 10

f (x) = \frac{1}{1000} (2 x - 1)^{3} + 10

What is the inverse of f(x)=((x+2))/((ax-1)) ?
The inverse of f(x)=((x+2))/((ax-1)) is (2+x)/(ax-1)