What is the inverse of f(x)=(sqrt(4-x^2))/3 ?

The inverse of f(x)=(sqrt(4-x^2))/3 is sqrt(-9x^2+4),-sqrt(-9x^2+4)

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inverse of f(x)=(sqrt(4-x^2))/3

inverse

f (x) = \frac{4 - x ^{2}}{3}

- 9 x^{2} + 4, - - 9 x^{2} + 4

Solution steps

y = \frac{4 - x ^{2}}{3}

Replace

x

with

y

x = \frac{4 - y ^{2}}{3}

Solve for

y, x = \frac{4 - y ^{2}}{3}

- 9 x^{2} + 4, - - 9 x^{2} + 4

f (x) = \frac{9 - 8 x}{10 x - 9}

y = - 5 x + 10

f (x) = 4 x + \frac{1}{3}

x - 8

1 2^{x}

What is the inverse of f(x)=(sqrt(4-x^2))/3 ?
The inverse of f(x)=(sqrt(4-x^2))/3 is sqrt(-9x^2+4),-sqrt(-9x^2+4)