What is the inverse of f(x)=4x^2+4x+1 ?

The inverse of f(x)=4x^2+4x+1 is (-1+sqrt(x))/2 ,-(sqrt(x)+1)/2

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inverse of f(x)=4x^2+4x+1

inverse

f (x) = 4 x^{2} + 4 x + 1

\frac{- 1 + x}{2}, - \frac{x + 1}{2}

Solution steps

y = 4 x^{2} + 4 x + 1

Replace

x

with

y

x = 4 y^{2} + 4 y + 1

Solve for

y, x = 4 y^{2} + 4 y + 1

\frac{- 1 + x}{2}, - \frac{x + 1}{2}

X^{2}

f (x) = 19 x

3^{x + 2} - 6

f (x) = - 2 e^{- x + 1} + 3

f (x) = sin (\frac{1 - 3 x}{x})

What is the inverse of f(x)=4x^2+4x+1 ?
The inverse of f(x)=4x^2+4x+1 is (-1+sqrt(x))/2 ,-(sqrt(x)+1)/2