What is the inverse of f(x)=15x^3-5 ?

The inverse of f(x)=15x^3-5 is cube root of (x+5)/(15)

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inverse of f(x)=15x^3-5

inverse

f (x) = 15 x^{3} - 5

Solution steps

y = 15 x^{3} - 5

Replace

x

with

y

x = 15 y^{3} - 5

Solve for

y, x = 15 y^{3} - 5

\frac{x ^{2} + 3 x - 1}{7 x - 4}

f (x) = \frac{x}{( x ^{2} + 1 )}

f (x) = (x + 4)^{2}, x \geq 0

x^{2} + 6 x + 9

What is the inverse of f(x)=15x^3-5 ?
The inverse of f(x)=15x^3-5 is cube root of (x+5)/(15)