What is the inverse of (x^2+3x-10)/(x^2-4) ?

The inverse of (x^2+3x-10)/(x^2-4) is (5-2x)/(x-1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of (x^2+3x-10)/(x^2-4)

inverse

\frac{x ^{2} + 3 x - 10}{x ^{2} - 4}

\frac{5 - 2 x}{x - 1}

Solution steps

y = \frac{x ^{2} + 3 x - 10}{x ^{2} - 4}

Replace

x

with

y

x = \frac{y ^{2} + 3 y - 10}{y ^{2} - 4}

Solve for

y, x = \frac{y ^{2} + 3 y - 10}{y ^{2} - 4}

\frac{5 - 2 x}{x - 1}

f (x) = \frac{1}{1 + x ^{4}}

f (x) = 3.5 (2.2)^{x}

f (x) = (6 x^{3} + 7)^{\frac{1}{5}}

f (x) = \frac{3}{2} x - \frac{1}{3}

What is the inverse of (x^2+3x-10)/(x^2-4) ?
The inverse of (x^2+3x-10)/(x^2-4) is (5-2x)/(x-1)